In a​ company, 85​% of the workers are . If 435 people work for the company who​ aren't ​, how many workers are there in​ all? Use pencil and paper. Show two different ways that you can solve this problem.

Answer:

\(\frac{1}{11}\)

Step-by-step explanation:

11 is \(\frac{11}{1\\}\) so to get the reciprocal just flip it to \(\frac{1}{11}\)

To reflect a point over the y-axis, we negate the x-coordinate of the point. To reflect the resulting point over the x-axis, we negate the y-coordinate of the point. So, to find the new point A'', we can perform these operations on the original point A:

1. Reflect A over the y-axis to get A': (-2, 2)

2. Reflect A' over the x-axis to get A'': (-2, -2)

Therefore, the new point A'' is (-2, -2).

Answer:

d. x = 7

Step-by-step explanation:

\(\frac{32}{8} = \frac{28}{x}\)

Cross multiply, the denominator "8" is multiplied by numerator "28", while the numerator "32" is multiplied by denominator "x":

8 * 28 = 224

32 * x = 32x

\(32x = 224\)

Divide both sides by 32:

\(\frac{32}{32} = \frac{224}{32}\)

[x = 7]

Answer:

\(226.2m^2\)

Step-by-step explanation:

\(A_L=2\pi rh=2*\pi *4.5*8\\=226.19467\\=226.1947\\=226.195\\=226.2m^2\)

The profit function for this problem is given as follows:

P(x) = -0.5x³ + 100x² - 500x + 300.

The profit function is obtained as the subtraction of the revenue function by the cost function, as follows:

P(x) = R(x) - C(x).

The functions for this problem are given as follows:

Hence the profit function is given as follows:

P(x) = -0.5x³ + 600x² - 200x + 300 - 500x² - 300x

P(x) = -0.5x³ + 100x² - 500x + 300.

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Select a random sample from each voting district based on the proportion of city residents in the district so that a total of 500 is obtained.

The correct option is (B).

Now, According to the question:

Stratified sampling design divides the given population into small sub-groups called strata. The members of each strata share some common features and at any particular time, a sample is randomly selected from each stratum which is then compared to the entire population. During random sampling, a number proportional to the stratum size is selected from all strata. The randomly selected samples from each strata are then combined to form a common random sample.

Considering that the editor wants to adopt stratified sampling, option B fits (Select a random sample from each voting district based on the proportion of city residents in the district so that a total of 500 is obtained.)

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The complete question is this:

A newspaper editor wants to investigate whether residents of the city support a proposal to build a new high school football stadium. The editor hires a polling firm to conduct a survey and requests that a sample of 500 residents be selected using a stratified sampling design based on voting districts within the city. Which of the following methods will achieve the desired sampling design?

(A) Send a survey to all city residents and use the first 500 returned surveys for the sample.

(B) Select a random sample from each voting district based on the proportion of city residents in the district so that a total of 500 is obtained.

(C) Select one voting district at random, and then select a random sample of 500 from the selected voting district.

(D) Alphabetize a list of all city residents, and then select the first 500 residents on the list, classifying those selected by voting district.

(E) Select the first 500 city residents who attend the next high school football game.

Answer:

Step-by-step explanation:

The histogram shows the distribution of the newly planted trees

The dataset is given as:

3.2, 4.3, 3.5, 5.4, 3.7, 5.5, 6.2, 3.1, 6.8, 7.1, 4.8, 6.5, 4.9, 5.3, 5.9

Sort the data elements

3.1, 3.2, 3.5, 3.7, 4.3, 4.8, 4.9, 5.3, 5.4, 5.5, 5.9, 6.2, 6.5, 6.8, 7.1

Calculate the range

Range = Highest - Least

This gives

Range = 7.1 - 3.1

Range = 4

Divide by 4 to calculate the class width

Width = 4/4

Width = 1

So, the classes and the frequencies are:

Class               Frequency

3.1 - 4.0              4

4.1 - 5.0              3

5.1 - 6.0             4

6.1 - 7.0              3

7.1 - 8.0              1

See attachment for the histogram

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Answer:

1. A, C

2. A, D

Step-by-step explanation:

The mutually exclusive events are one which cannot happen together. The observation is made regarding with which students live. They live with either one of their biological parent or grandparent. The student have the option to live with two legally married couple this is mutually exclusive event. If the student is living with their one biological parent he cannot live with two legally married parents.

Answer:

Problem 20: \(m\) = \(2\)

Problem 21: \(m\) = \(-2\)

Problem 22: \(m\) = \(1\)

Problem 23: \(m\) = \(3\)

Step-by-step explanation:

The formula to find the slope of a line: \(m = \frac{y_{2} - y_{1}}{x_{2}-x_{1}}\).

Problem 20:

1) Substitute the values into the formula and solve it.

\(m\) = \(\frac{3-7}{2-4}\)

\(m\) = \(\frac{-4}{-2}\)

\(m\) = \(2\)

Problem 21:

1) Substitute the values into the formula and solve it.

\(m\) = \(\frac{-5-1}{2--1}\)

\(m\) = \(\frac{-6}{3}\)

\(m\) = \(-2\)

Problem 22:

1) Substitute the values into the formula and solve it.

\(m\) = \(\frac{3-7}{-6--2}\)

\(m\) = \(\frac{-4}{-4}\)

\(m\) = \(1\)

Problem 23:

1) Substitute the values into the formula and solve it.

\(m\) = \(\frac{-4-2}{-4--2}\)

\(m\) = \(\frac{-6}{-2}\)

\(m\) = \(3\)

*Extra*: The equation of a line is written in this form: \(y = mx+b\), where \(m\) is the slope and \(b\) is \(y\)-intercept

Answer: Use the distributive property to multiply 3 by y−4.

3y−12−2(y−4)

Use the distributive property to multiply −2 by y−4.

3y−12−2y+8

Combine 3y and −2y to get y.

y−12+8

Add −12 and 8 to get −4.

Anwser:

y−4

Step-by-step explanation:

Hope this helps!

The correct equivalent expression to the square root containing a variable is 2a³/5 and the correct option is E.

We shall simplify the expression of the square root containing a variable by carrying out basic mathematics operations to derive its equivalent as follows:

squre root of (36a⁸/255a²) = square root of (36a⁶ × a²/255 × a²)

a² is common and can be cancel out

square root of (36a⁸/255a²) = square root of (36a⁶/255)

square root of (36a⁸/255a²) = square of 36 multiplied by the square root of a⁶ all divided by the square root of 255 {take square root of each}

square root of (36a⁸/255a²) = 6a³/15

square root of (36a⁸/255a²) = 2a³ × 3/5 × 3

we divide through by the common factor 3

square root of (36a⁸/255a²) = 2a³/5

Therefore, the equivalent expression to square root of (36a⁸/255a²) is derived as 2a³/5 which is option E.

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The mode will not change.

Given data,

58,60,53,54,60,35,58,60

Outlier is the value in a set of data that much higher or lower than other values in data.

from given data, outlier is 35.

Mode is the value in a set of data that occurs more frequently in set of data.

from given data, 60 occurs more frequently.

Hence, 60 is the mode of data.

If outlier is removed from the data set then it will not affect the mode of the data

Thus, the mode will not change.

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Answer:

91.................

Answer:

Step-by-step explanation:

4.5

The number of the pounds of sugar that you need for triple batch will be 72 ounces.

A ratio is a collection of ordered integers a and b represented as a/b, with b never equaling zero. A proportionate expression is one in which two items are equal.

You have a pickle recipe that requires 24 ounces of sugar.

You want to make a triple batch of pickles.

Then the number of the pounds of sugar that you need for triple batch will be

⇒ 3 x 24

⇒ 72 ounces

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The correct answer is: O Yes, distance and angle measure are preserved.

When a triangle ABC is reflected across the line y = x, the pre-image and image are congruent.

This is because the line y = x is the perpendicular bisector of the segment joining each corresponding point of the pre-image and image.

Reflection across the line y = x is a type of transformation known as an isometry, which preserves both distance and angle measure.

Here's why:

Distance preservation:

When a point is reflected across the line y = x, the distance between the original point and its reflection remains the same.

This holds true for all corresponding points of the triangle.

Therefore, the distance between any two corresponding points in the pre-image and image triangle will be equal, resulting in distance preservation.

Angle preservation: When a line segment is reflected across the line y = x, the angle between the line segment and the line y = x is preserved. This means that the corresponding angles in the pre-image and image triangle will be congruent.

Since both distance and angle measure are preserved during reflection across the line y = x, the pre-image and image triangles are congruent.

It's important to note that congruence under reflection across a line holds only when the line of reflection is the same for both the pre-image and image.

If the line of reflection were different, the triangles would not be congruent.

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Let's call the rate paid by Stefan as r1 on the first spot and r2 on the second spot and the amount of hours he parked as h. On the first parking spot, he can pay a flat rate of $8, this gives to us the following equation for the cost on the first place

Or, in the second place, he can pay $1 per parked hour, which gives us the following equation

Since for the length of time Stefan spent on Fairview both options were equivalent, we have

From the first equation, we know that he spent $8 and by the second equation we know that he spent 8 hours.

1. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

2. Probability of no breakdowns = (reliability of a single machine)^3. Probability of at least one breakdown = 1 - Probability of no breakdowns

1. To determine how often the computer should be scheduled for maintenance, we need to consider the reliability and the desired level of operational condition. Since the duration for trouble-free operation follows a gamma distribution with a mean of 40 days, this means that, on average, the computer can operate for 40 days before a breakdown occurs.

To ensure operational condition with a 95% probability, we can calculate the maintenance interval using the concept of reliability. The reliability represents the probability that the machine will not break down within a certain time period. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

Using the gamma distribution parameters, we can find the corresponding reliability for a specific time duration. By setting the reliability equation equal to 0.95 and solving for time, we can find the maintenance interval:

reliability = 0.95

time = maintenance interval

Using reliability and the gamma distribution parameters, we can calculate the maintenance interval.

2. To calculate the probability that at least one of the three machines will break down within the first scheduled maintenance time, we can use the complementary probability approach.

The probability that none of the machines will break down within the first scheduled maintenance time is given by the reliability of a single machine raised to the power of the number of machines:

Probability of no breakdowns = (reliability of a single machine)^3

Since the breakdown times between the machines are statistically independent, we can assume that the reliability of each machine is the same. Therefore, we can use the reliability calculated in the first part and substitute it into the formula:

Probability of at least one breakdown = 1 - Probability of no breakdowns

By calculating this expression, we can determine the probability that at least one of the three machines will break down within the first scheduled maintenance time.

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For the function,

F(x)  = (x² + 11x +28)/(x² + 8x + 15) limit doesn't exist at x = -5 so it is dis-continuous at that point.

In mathematics, The function is called as continuous at the particular value of x,  if right hand limit, left hand limit and the value of function at x all are equal.

RHL   = LHL  = F(x)

Limit exist and continuous

Given that,

F(x)  = (x² + 11x +28)/(x² + 8x + 15)

To check whether it is continuous at x = -5

First taking LHL,

\(\lim_{h \to \ 0}\) [(-5-h)² + 11(-5 -h) +28]/[(-5 -h)² + 8(-5 -h) + 15]

It is approaching at negative infinity

Now, taking RHL

\(\lim_{h \to \ 0}\)  [(-5+h)² + 11(-5 +h) +28]/[(-5 +h)² + 8(-5+h) + 15]

Again, It is approaching at negative infinity

Hence, here limit doesn't exist so it is not continuous at x = -5

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Answer:

X=32, Y=148

Step-by-step explanation:

X is 32 degrees because it is parallel to that 32 between f and b.

Y is 148 degrees because x and y together make a straight line and a straight line is 180 degrees therefore, 180-32 = 148.

a) The radius of the sphere is given as follows: 27.13 ft.

b) The surface area can be checked as follows: S = 4 x 3.14 x 27.13² = 9244.

The surface area for a sphere of radius r is given by the equation presented as follows:

S = 4πr².

The surface area for this problem is given as follows:

9244 ft².

Hence the radius is given as follows:

\(r = \sqrt{\frac{9244}{4 \times 3.14}}\)

r = 27.13 ft.

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Answer:

2 1/2

Step-by-step explanation:

(These are fractions)

1+3 ÷ 2

4 5

(Simplify)

4 ÷ 2

4 5

(Same denominator)

20 ÷ 8

20 20

(Divide)

2 1/2

The time spent higher than 26 meters above the ground is 0.42 minutes. Answer: 0.42

A Ferris wheel is 30 meters in diameter and boarded from a platform that is 4 meters above the ground.

The six o'clock position on the Ferris wheel is level with the loading platform.

The wheel completes 1 full revolution in 2 minutes.

We have to find how many minutes of the ride are spent higher than 26 meters above the ground.

So, let's start with some given data,Consider the height of a person at the six o'clock position = 4 meters

So, the height of a person at the highest point = 4 + 15 = 19 meters (since the diameter is 30 meters, the radius will be 15 meters)

Also, the height of a person at the lowest point = 4 - 15 = -11 meters

Therefore, the Ferris wheel completes one cycle from the lowest point to the highest point and back to the lowest point.

So, the total distance travelled will be = 19 + 11 = 30 meters.

Also, we are given that the wheel completes 1 full revolution in 2 minutes.

We need to calculate the time spent higher than 26 meters above the ground.

So, the angle between the 6 o'clock position and 2 o'clock position will be equal to the angle between the 6 o'clock position and the highest point.

This angle can be calculated as follows:

Angle = Distance travelled by the Ferris wheel / Circumference of the Ferris wheel * 360 degrees

Angle = 30 / (pi * 30) * 360 degrees

Angle = 360 degrees / pi

= 114.59 degrees

So, the total angle between the 6 o'clock position and the highest point is 114.59 degrees.

Now, we need to find out how much time is spent at an angle greater than 114.59 degrees.

This can be calculated as follows:

Time = (Angle greater than 114.59 degrees / Total angle of the Ferris wheel) * Total time taken

Time = (180 - 114.59) / 360 * 2 minutes

Time = 0.42 minutes

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Answer:

Mr. Ehrig is at the lowest elevation. AND .Mrs. White is closest to street level.

Step-by-step explanation:

Answer:

She would have 3 quarters, 3 dimes, and 1 nickel.

The angle measures for this problem are given as follows:

The sum of the measures of the internal angles of a triangle is of 180º.

The triangle in this problem is ABC, hence the measure of a is obtained as follows:

a + 68 + 50 = 180

a = 180 - (68 + 50)

a = 62º.

c and d are corresponding angles to angle a, as they are on the same position relative to parallel lines, hence their measures are given as follows:

Angle b is a corresponding interior angle with angle a, hence they are supplementary and it's measure is given as follows:

a + b = 180

62 + b = 180

b = 118º.

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Answer: This is a tough question

Depends on if you wanna cook it medium rare, rare, medium well, well done, or do you just wanna eat it raw :D

Step-by-step explanation:

He isn't lucky nor unlucky

Step-by-step explanation:

If The owner Wins every round/time he has to be skilled if he's winning for several hours